document.write( "Question 117838: Graph the equation.\r
\n" ); document.write( "\n" ); document.write( "y=x+1
\n" ); document.write( "

Algebra.Com's Answer #85829 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=1%2Ax%2B1\" we only need to plug in two points to draw the line
\n" ); document.write( "
\n" ); document.write( " So lets plug in some points
\n" ); document.write( "
\n" ); document.write( " Plug in x=-9
\n" ); document.write( "
\n" ); document.write( " \"y=1%2A%28-9%29%2B1\"
\n" ); document.write( "
\n" ); document.write( " \"y=-9%2B1\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=-8\" Add
\n" ); document.write( "
\n" ); document.write( " So here's one point (-9,-8)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now lets find another point
\n" ); document.write( "
\n" ); document.write( " Plug in x=-8
\n" ); document.write( "
\n" ); document.write( " \"y=1%2A%28-8%29%2B1\"
\n" ); document.write( "
\n" ); document.write( " \"y=-8%2B1\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=-7\" Add
\n" ); document.write( "
\n" ); document.write( " So here's another point (-8,-7). Add this to our graph
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now draw a line through these points
\n" ); document.write( "
\n" ); document.write( " So this is the graph of \"y=1%2Ax%2B1\" through the points (-9,-8) and (-8,-7)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So from the graph we can see that the slope is \"1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 1 units to get to the next point) the y-intercept is (0,\"1\")and the x-intercept is (\"-1\",0)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " We could graph this equation another way. Since \"b=1\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"1\").
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So we have one point (0,\"1\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now since the slope is \"1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"1\"), we can go up 1 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and to the right 1 units to get to our next point
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now draw a line through those points to graph \"y=1%2Ax%2B1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the graph of \"y=1%2Ax%2B1\" through the points (0,1) and (1,2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );