document.write( "Question 117827: Factor completely. 6x^2+7x+2 \n" ); document.write( "
Algebra.Com's Answer #85820 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at \"6x%5E2%2B7x%2B2\" we can see that the first term is \"6x%5E2\" and the last term is \"2\" where the coefficients are 6 and 2 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 6 and the last coefficient 2 to get 12. Now what two numbers multiply to 12 and add to the middle coefficient 7? Let's list all of the factors of 12:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 12:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,12\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-12 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 12\r
\n" ); document.write( "\n" ); document.write( "1*12\r
\n" ); document.write( "\n" ); document.write( "2*6\r
\n" ); document.write( "\n" ); document.write( "3*4\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-12)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-6)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(-4)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7\r
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First NumberSecond NumberSum
1121+12=13
262+6=8
343+4=7
-1-12-1+(-12)=-13
-2-6-2+(-6)=-8
-3-4-3+(-4)=-7
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 3 and 4 add up to 7 and multiply to 12\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"6x%5E2%2B7x%2B2\", replace \"7x\" with \"3x%2B4x\" (notice \"3x%2B4x\" adds up to \"7x\". So it is equivalent to \"7x\")\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2Bhighlight%283x%2B4x%29%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"6x%5E2%2B3x%2B4x%2B2\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%286x%5E2%2B3x%29%2B%284x%2B2%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"3x%282x%2B1%29%2B2%282x%2B1%29\" Factor out the GCF of \"3x\" out of the first group. Factor out the GCF of \"2\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%2B2%29%282x%2B1%29\" Since we have a common term of \"2x%2B1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"6x%5E2%2B3x%2B4x%2B2\" factors to \"%283x%2B2%29%282x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"6x%5E2%2B7x%2B2\" factors to \"%283x%2B2%29%282x%2B1%29\" (since \"6x%5E2%2B7x%2B2\" is equivalent to \"6x%5E2%2B3x%2B4x%2B2\")\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"6x%5E2%2B7x%2B2\" factors to \"%283x%2B2%29%282x%2B1%29\"\r
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