document.write( "Question 117820: Multiply. (3x – 1)(2x + 5) \n" ); document.write( "
Algebra.Com's Answer #85811 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%283x-1%29%282x%2B5%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283x%29-1%29%28highlight%282x%29%2B5%29\" Multiply the First terms:\"%283x%29%2A%282x%29=6x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283x%29-1%29%282x%2Bhighlight%285%29%29\" Multiply the Outer terms:\"%283x%29%2A%285%29=15x\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%2Bhighlight%28-1%29%29%28highlight%282x%29%2B5%29\" Multiply the Inner terms:\"%28-1%29%2A%282x%29=-2x\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%2Bhighlight%28-1%29%29%282x%2Bhighlight%285%29%29\" Multiply the Last terms:\"%28-1%29%2A%285%29=-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2B15x-2x-5\" Now collect every term to make a single expression\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2B13x-5\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"%283x-1%29%282x%2B5%29\" foils and simplifies to \"6x%5E2%2B13x-5\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%283x-1%29%282x%2B5%29=6x%5E2%2B13x-5\"\r
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