document.write( "Question 117642: THE SPEED OF AN AIRPLANE IN STILL AIR IS 224KM/H. THE PLANE TRAVELS 733KM AGAINST THE WIND AND 1075KM WITH THE WIND IN A TOTAL TIME OF 15HR. WHAT IS THE SPEED OF THE WIND \n" ); document.write( "
Algebra.Com's Answer #85810 by ankor@dixie-net.com(22740)\"\" \"About 
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THE SPEED OF AN AIRPLANE IN STILL AIR IS 224KM/H. THE PLANE TRAVELS 733KM AGAINST THE WIND AND 1075KM WITH THE WIND IN A TOTAL TIME OF 15 HR. WHAT IS THE SPEED OF THE WIND
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\n" ); document.write( "Let x = wind speed
\n" ); document.write( "then
\n" ); document.write( "(224-x) = speed against the wind
\n" ); document.write( "and
\n" ); document.write( "(224+x) = speed with the wind
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\n" ); document.write( "The total time is given as 15 hrs, write a time equation: Time = Dist/speed
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\n" ); document.write( "Time with + time against = 15 hrs
\n" ); document.write( "\"1075%2F%28%28224%2Bx%29%29\" + \"733%2F%28%28224-x%29%29\" = 15
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\n" ); document.write( "Multiply equation by (224+x)(224-x) to get rid of the denominators, results
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\n" ); document.write( "1075(224-x) + 733(224+x) = 15(224+x)(224-x)
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\n" ); document.write( "240800 - 1075x + 164192 + 733x = 15(50176 - x^2)
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\n" ); document.write( "-1075x + 733x + 240800 + 164192 = 752640 - 15x^2
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\n" ); document.write( "+15x^2 - 342x + 404992 - 752640 = 0; arrange as a quadratic equation
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\n" ); document.write( "15x^2 - 342x - 347648 = 0
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\n" ); document.write( "Solve this using the quadratic formula; a=15, b=-342, c=-347648
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\n" ); document.write( "I got a positive solution (approximately): x = 164.06 is the speed of the wind
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\n" ); document.write( "Checking our solution:
\n" ); document.write( "224 - 164.06 = 59.94 km/hr against the wind
\n" ); document.write( "and
\n" ); document.write( "224 + 164.06 = 388.06 km/hr with the wind
\n" ); document.write( ":
\n" ); document.write( "1075/388.06 + 733/59.94 =
\n" ); document.write( "2.77 + 12.23 = 15 hrs
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