document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2154>Question 2154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A postal truck leaves its station and heads for Chicago, averaging 40mph. An error in the mailing schedule is spotted and 24 min. after the truck leaves, a car is sent to overtake the truck. If the car averages 50mph, how long will it take to catch the postal truck? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #858 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If the give two speeds are v1(< v2) with distance D,then<BR>\n" );
document.write( " the time for the 2nd vehicle to overtake the 1st vehicle is<BR>\n" );
document.write( "  T = D/(v2 - v1).\r<BR>\n" );
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document.write( " Now,D = 40* 24/60 = 40* 2/5 = 16 miles,\r<BR>\n" );
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document.write( " Hence, T = 16/(50-40) = 1.6 hours\r<BR>\n" );
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document.write( " We learned this question in primary school,so you have to<BR>\n" );
document.write( " work hard. </SPAN>\n" );
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