document.write( "Question 117783: Write the equation of the L satisfying the given geometric conditions.\r
\n" ); document.write( "\n" ); document.write( "L passes through point (-4,3) and is parallel to the line equation y=2x+1
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Algebra.Com's Answer #85784 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"2\" (its from the slope of \"y=2%2Ax%2B1\" which is also \"2\").\n" ); document.write( "Also since the unknown line goes through (-4,3), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-3=2%2A%28x%2B4%29\" Plug in \"m=2\", \"x%5B1%5D=-4\", and \"y%5B1%5D=3\"
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\n" ); document.write( " \"y-3=2%2Ax-%282%29%28-4%29\" Distribute \"2\"
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\n" ); document.write( " \"y-3=2%2Ax%2B8\" Multiply
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\n" ); document.write( " \"y=2%2Ax%2B8%2B3\"Add \"3\" to both sides to isolate y
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\n" ); document.write( " \"y=2%2Ax%2B11\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=2%2Ax%2B1\" and goes through (\"-4\",\"3\") is \"y=2%2Ax%2B11\"
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\n" ); document.write( " So here are the graphs of the equations \"y=2%2Ax%2B1\" and \"y=2%2Ax%2B11\"
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\n" ); document.write( " graph of the given equation \"y=2%2Ax%2B1\" (red) and graph of the line \"y=2%2Ax%2B11\"(green) that is parallel to the given graph and goes through (\"-4\",\"3\")
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