document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117708>Question 117708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "If angle RMK=5x+8, angle KMT=3x-5, and angle TML=6x+17, then x=_______<BR>\n" );
document.write( "a. 10<BR>\n" );
document.write( "b. 4<BR>\n" );
document.write( "c. 5<BR>\n" );
document.write( "d. 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85757 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF THESE ARE COMPLEMENTARY ANGLES THEN THEIR SUM=90 DEGREES.<BR>\n" );
document.write( "5X+8+3X-5+6X+17=90<BR>\n" );
document.write( "14X+20=90<BR>\n" );
document.write( "14X=70<BR>\n" );
document.write( "X=70/14<BR>\n" );
document.write( "X=5 DEGREES ANSWER.<BR>\n" );
document.write( "IF THEY ARE SUPPLIMENTARY ANGLES THEIR SUM=180 DEGREES.<BR>\n" );
document.write( "5X+8=3X-5+6X+17=180<BR>\n" );
document.write( "14X+20=180<BR>\n" );
document.write( "14X=180-20<BR>\n" );
document.write( "X=160/14<BR>\n" );
document.write( "X=11.42857 DEGREES.  </SPAN>\n" );
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