document.write( "Question 117772This question is from textbook Algebra 1
\n" ); document.write( ": how do you factor 2x^2+11x+5? \n" ); document.write( "
Algebra.Com's Answer #85756 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Looking at \"2x%5E2%2B11x%2B5\" we can see that the first term is \"2x%5E2\" and the last term is \"5\" where the coefficients are 2 and 5 respectively.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 2 and the last coefficient 5 to get 10. Now what two numbers multiply to 10 and add to the middle coefficient 11? Let's list all of the factors of 10:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factors of 10:\r
\n" ); document.write( "\n" ); document.write( "1,2,5,10\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1,-2,-5,-10 ...List the negative factors as well. This will allow us to find all possible combinations\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 10\r
\n" ); document.write( "\n" ); document.write( "1*10\r
\n" ); document.write( "\n" ); document.write( "2*5\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-10)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-5)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 11? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 11\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
First NumberSecond NumberSum
1101+10=11
252+5=7
-1-10-1+(-10)=-11
-2-5-2+(-5)=-7
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From this list we can see that 1 and 10 add up to 11 and multiply to 10\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"2x%5E2%2B11x%2B5\", replace \"11x\" with \"1x%2B10x\" (notice \"1x%2B10x\" adds up to \"11x\". So it is equivalent to \"11x\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2Bhighlight%281x%2B10x%29%2B5\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's factor \"2x%5E2%2B1x%2B10x%2B5\" by grouping:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282x%5E2%2B1x%29%2B%2810x%2B5%29\" Group like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%282x%2B1%29%2B5%282x%2B1%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"5\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%282x%2B1%29\" Since we have a common term of \"2x%2B1\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B1x%2B10x%2B5\" factors to \"%28x%2B5%29%282x%2B1%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So this also means that \"2x%5E2%2B11x%2B5\" factors to \"%28x%2B5%29%282x%2B1%29\" (since \"2x%5E2%2B11x%2B5\" is equivalent to \"2x%5E2%2B1x%2B10x%2B5\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B11x%2B5\" factors to \"%28x%2B5%29%282x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );