document.write( "Question 117740: The length of a rectangle is 7/8 yd, and its width is 32/49 yd. What is its area in square yards?
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Algebra.Com's Answer #85709 by MathLover1(20850) $\"\"$ $\"About$

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let the length of a rectangle be $\"a+=%287%2F8%29yd\"$ and its width be $\"b=%2832%2F49%29+yd\"$
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\n" ); document.write( "\n" ); document.write( " $\"A+=+a%2Ab\"$ ....substitute $\"a\"$ and $\"b\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"A+=+%287%2F8%29yd%2A%2832%2F49%29yd\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"A+=+%287%2F8%29%2832%2F49%29yd%5E2\"$ ЕЕЕЕЕ.\r
\n" ); document.write( "\n" ); document.write( " $\"A+=+%28%287%2A32%29%2F%288%2A49%29%29yd%5E2\"$ ЕЕЕЕЕ.simplify..(divide $\"7\"$ and $\"49\"$ by $\"7\"$ , as $\"8\"$ and $\"32\"$ by $\"8\"$ as well)\r
\n" ); document.write( "\n" ); document.write( " $\"A+=+%28%281%2A4%29%2F%281%2A7%29%29yd%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"A+=+%284%2F7%29yd%5E2\"$
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