document.write( "Question 117686: Solve the system by substitution.\r
\n" ); document.write( "\n" ); document.write( "x + 4y = -4
\n" ); document.write( "3x - 3y = -12\r
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Algebra.Com's Answer #85681 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax%2B4%2Ay=-4\"
\n" ); document.write( " \"3%2Ax-3%2Ay=-12\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"4%2Ay=-4-1%2Ax\"Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%28-4-1%2Ax%29%2F4\" Divide both sides by 4.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=-1-%281%2F4%29%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"-1-%281%2F4%29%2Ax\" we can substitute the expression \"-1-%281%2F4%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"3%2Ax%2B-3%2Ahighlight%28%28-1-%281%2F4%29%2Ax%29%29=-12\" Replace y with \"-1-%281%2F4%29%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"3%2Ax-3%2A%28-1%29-3%28-1%2F4%29x=-12\" Distribute -3 to \"-1-%281%2F4%29%2Ax\"
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\n" ); document.write( " \"3%2Ax%2B3%2B%283%2F4%29%2Ax=-12\" Multiply
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\n" ); document.write( " \"3%2Ax%2B3%2B%283%2F4%29%2Ax=-12\" Reduce any fractions
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\n" ); document.write( " \"3%2Ax%2B%283%2F4%29%2Ax=-12-3\" Subtract \"3\" from both sides
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\n" ); document.write( " \"3%2Ax%2B%283%2F4%29%2Ax=-15\" Combine the terms on the right side
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\n" ); document.write( " \"%2812%2F4%29%2Ax%2B%283%2F4%29x=-15\" Make 3 into a fraction with a denominator of 4
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\n" ); document.write( " \"%2815%2F4%29%2Ax=-15\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%284%2F15%29%2815%2F4%29%29x=%28-15%2F1%29%284%2F15%29\" Multiply both sides by \"4%2F15\". This will cancel out \"15%2F4\" and isolate x
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\n" ); document.write( " So when we multiply \"-15%2F1\" and \"4%2F15\" (and simplify) we get
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\n" ); document.write( " \"x=-4\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=-4\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"3%28-4%29-3%2Ay=-12\" Plug in \"x=-4\" into the 2nd equation
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\n" ); document.write( " \"-12-3%2Ay=-12\" Multiply
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\n" ); document.write( " \"-3%2Ay=-12%2B12\"Add \"12\" to both sides
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\n" ); document.write( " \"-3%2Ay=0\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-3%29%28-3%29%29%2Ay=%280%2F1%29%281%2F-3%29\" Multiply both sides by \"1%2F-3\". This will cancel out -3 on the left side.
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\n" ); document.write( " \"y=0%2F-3\" Multiply the terms on the right side
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\n" ); document.write( " \"y=0\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=0\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=-4\" and \"y=0\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"-4\",\"0\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax%2B4%2Ay=-4\"
\n" ); document.write( " \"3%2Ax-3%2Ay=-12\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax%2B4%2Ay=-4\" (red) and \"3%2Ax-3%2Ay=-12\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"-4\",\"0\"). This verifies our answer.
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\n" ); document.write( " -----------------------------------------------------------------------------------------------
\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"-4\",\"0\") into the system of equations
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\n" ); document.write( " Let \"x=-4\" and \"y=0\". Now plug those values into the equation \"1%2Ax%2B4%2Ay=-4\"
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\n" ); document.write( " \"1%2A%28-4%29%2B4%2A%280%29=-4\" Plug in \"x=-4\" and \"y=0\"
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\n" ); document.write( " \"-4%2B0=-4\" Multiply
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\n" ); document.write( " \"-4=-4\" Add
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\n" ); document.write( " \"-4=-4\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-4\",\"0\") satisfies \"1%2Ax%2B4%2Ay=-4\"
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\n" ); document.write( " Let \"x=-4\" and \"y=0\". Now plug those values into the equation \"3%2Ax-3%2Ay=-12\"
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\n" ); document.write( " \"3%2A%28-4%29-3%2A%280%29=-12\" Plug in \"x=-4\" and \"y=0\"
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\n" ); document.write( "
\n" ); document.write( " \"-12%2B0=-12\" Multiply
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\n" ); document.write( " \"-12=-12\" Add
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\n" ); document.write( "
\n" ); document.write( " \"-12=-12\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-4\",\"0\") satisfies \"3%2Ax-3%2Ay=-12\"
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\n" ); document.write( " Since the solution (\"-4\",\"0\") satisfies the system of equations
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\n" ); document.write( " \"1%2Ax%2B4%2Ay=-4\"
\n" ); document.write( " \"3%2Ax-3%2Ay=-12\"
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\n" ); document.write( " this verifies our answer.
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