document.write( "Question 117654: what is the equation for finding the vertex to y=(1/4)(x^2-2x+5) \n" ); document.write( "
Algebra.Com's Answer #85658 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"y=%281%2F4%29%28x%5E2-2x%2B5%29\"
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\n" ); document.write( "\"y=%281%2F4%29x%5E2-+%281%2F4%292x%2B+%281%2F4%295\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29x%5E2-+%281%2F2%29x%2B+%285%2F4%29\"…….=>…\"a=1%2F4\",\"b=1%2F2\",and \"c=5%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "To find the value of “x” at the vertex, use this formula: \"x+=+-%28b%2F2a%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-%28%281%2F2%29%2F%282%281%2F4%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-%28%281%2F2%29%2F%282%2F4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-%28%281%2F2%29%2F%281%2F2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-%282%2F2%29\"\r
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\n" ); document.write( "\"x+=+-+1\"\r
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\n" ); document.write( "to find \"y\", substitute your answer for \"x+\" into the original equation to find the \"y\", value of the vertex\r
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\n" ); document.write( "\"y=%281%2F4%29%28x%5E2-2x%2B5%29\"…………….. \"x+=+-+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29%281%5E2-2%2A1+%2B5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29%281+-2+%2B5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=+1\"\r
\n" ); document.write( "\n" ); document.write( "So, the “point” of the vertex is: (\"-1\", \"1\"). This is the \"POINT\" where the quadratic equation will \"change\" direction on the graph.\r
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