document.write( "Question 117637: i was wondering how to solve log 3x=1 \n" ); document.write( "
Algebra.Com's Answer #85647 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"log%2810%2C%283x%29%29=1\" Start with the given equation. Note: Since you did not specify a base, this means that we're going to use the default base 10.\r
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\n" ); document.write( "\n" ); document.write( "\"10%5E%281%29=3x\" Rewrite the equation using the property: \"log%28b%2C%28x%29%29=y\" ====> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"10=3x\" Evaluate \"10%5E%281%29\" to get \"10\"\r
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\n" ); document.write( "\n" ); document.write( "\"10%2F3=x\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=10%2F3\" which is approximately \"x=3.333\"
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