document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117634>Question 117634</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 25 and the sum of their squares is 313.  Find the numbers.  (Express one number as x, the other in terms of x).\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85640 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=25 or x=25-y<BR>\n" );
document.write( "x^2+y^2=313 substitute (25-y) for x in this equation & solve for y<BR>\n" );
document.write( "(25-y)^2+y^2=313<BR>\n" );
document.write( "625-50y+y^2+y^2=313<BR>\n" );
document.write( "2y^2-50y+625-313=0<BR>\n" );
document.write( "2y^2-50y+312=0<BR>\n" );
document.write( "2(y^2-25y+156)=0<BR>\n" );
document.write( "2(y-13)(y-12)=0<BR>\n" );
document.write( "y-13=0<BR>\n" );
document.write( "y=13 answer.<BR>\n" );
document.write( "y-12=0<BR>\n" );
document.write( "y=12 answer.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "12^2=13^2=33<BR>\n" );
document.write( "144+169=313<BR>\n" );
document.write( "313=313\r<BR>\n" );
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