document.write( "Question 17710: If the length of a rectangular parking lot is 10 tard less than twice its width. if the perimeter of the lot is 400 yrads, what are its dimention? \n" ); document.write( "

Algebra.Com's Answer #8564 by xcentaur(357) $\"\"$ $\"About$

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let the length be x and width be y
\n" ); document.write( "then
\n" ); document.write( "x=2y-10.......[1]
\n" ); document.write( "2(x+y)=400....[2]
\n" ); document.write( "

\n" ); document.write( "substituting [1] in [2] we get
\n" ); document.write( "2(2y-10+y)=400
\n" ); document.write( "(2y-10+y)=200
\n" ); document.write( "3y-10=200
\n" ); document.write( "3y=210
\n" ); document.write( "y=70
\n" ); document.write( "

\n" ); document.write( "x=2y-10=140-10=130
\n" ); document.write( "

\n" ); document.write( "Dimensions are: 70 yards,130 yards
\n" ); document.write( "

\n" ); document.write( "Hope this helps,
\n" ); document.write( "Prabhat \n" ); document.write( "

\n" );