document.write( "Question 117631: AN ACCOUNTANT RIDES A BUS PART OF THE WAY TO WORK EVERY DAY AND WALK THE REST OF THE WAY. THE BUS AVERAGES 40MPH AND THE ACCOUNTANT WALKS AT A SPEED OF 3MPH.THE DISTANT FROM HOME TO WORK IS 22MI AND THE TOTAL TIME FOR THE TRIP IS
\n" ); document.write( "3 HOURS. FIND HOW FAR THE ACCOUNTANT WALKS.
\n" ); document.write( "

Algebra.Com's Answer #85634 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate x Time = Distance
\n" ); document.write( "Distance = Rate/Time
\n" ); document.write( "Let's call Bus Time and Bus Distance, T1 and D1.
\n" ); document.write( "Let's call walk time and walk distance, T2 and D2.
\n" ); document.write( "1.\"D1%2BD2=22\" Total distance is 22 miles.
\n" ); document.write( "2.\"T1%2BT2=3\" Total time is 3 hours.
\n" ); document.write( "3.\"D1%2FT1=40\" Rate of the bus is 40 mph.
\n" ); document.write( "4.\"D2%2FT2=3\" Rate of the accountant walking is 3 mph.
\n" ); document.write( "From 3,
\n" ); document.write( "3.\"D1%2FT1=40\"
\n" ); document.write( "\"D1=40T1\"
\n" ); document.write( "and from 4,
\n" ); document.write( "4.\"D2%2FT2=3\"
\n" ); document.write( "\"D2=3T2\"
\n" ); document.write( "You can substitute these values into 1.
\n" ); document.write( "1.\"D1%2BD2=22\"
\n" ); document.write( "\"40T1%2B3T2=22\"
\n" ); document.write( "\"3T2=22-40T1\"
\n" ); document.write( "\"T2=%2822-40T1%29%2F3\"
\n" ); document.write( "You can substitute this value for T2 into equation 2 and solve for T1.
\n" ); document.write( "2.\"T1%2BT2=3\"
\n" ); document.write( "\"T1%2B%2822-40T1%29%2F3=3\"
\n" ); document.write( "\"3T1%2B22-40T1=9\"
\n" ); document.write( "\"22-37T1=9\"
\n" ); document.write( "\"-37T1=-13\"
\n" ); document.write( "\"T1=13%2F37\"
\n" ); document.write( "From 2,
\n" ); document.write( "\"T1%2BT2=3\"
\n" ); document.write( "\"13%2F37%2BT2=3\"
\n" ); document.write( "\"T2=3-14%2F37\"
\n" ); document.write( "\"T2=111%2F37-13%2F37\"
\n" ); document.write( "\"T2=98%2F37\"
\n" ); document.write( "From 3,
\n" ); document.write( "\"D1=40T1\"
\n" ); document.write( "\"D1=40%2813%2F37%29\"
\n" ); document.write( "\"D1=520%2F37\"
\n" ); document.write( "From 4,
\n" ); document.write( "\"D2=3T2\"
\n" ); document.write( "\"D2=3%2898%2F37%29\"
\n" ); document.write( "\"D2=294%2F37\"
\n" ); document.write( "So in approximate terms, the accountant rides the bus 14.1 miles for 0.35 hrs(21 minutes).
\n" ); document.write( "Then walks 2.65 hrs (2 hrs, 39 minutes) for a distance of 7.9 miles.
\n" ); document.write( "Total distance is 14.1+7.9 or 22 miles.
\n" ); document.write( "Total time is 0.35+2.65 or 3 hours.
\n" ); document.write( "
\n" );