document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117473>Question 117473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
document.write( "\n" );
document.write( "The larger of two supplementary angles is 40 degrees less than 3 times the smaller. Find both angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85619 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+3X-40=180<BR>\n" );
document.write( "4X=180+40<BR>\n" );
document.write( "4X=220<BR>\n" );
document.write( "X=220/4<BR>\n" );
document.write( "X=55 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "180-55=125 FOR THE LARGER ANGLE.<BR>\n" );
document.write( "55+3*55-40=180<BR>\n" );
document.write( "55+165-40=180<BR>\n" );
document.write( "220-40=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );