document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117522>Question 117522</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem. Thank you!\r<BR>\n" );
document.write( "\n" );
document.write( "3x-y=4<BR>\n" );
document.write( "3x+2y=-17 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85612 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X-Y=4 NOW MULTIPLY THE SECOND EQUATION BY -1 & ADD.<BR>\n" );
document.write( "-3X-2Y=17<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "-3Y=21<BR>\n" );
document.write( "Y=21/-3<BR>\n" );
document.write( "Y=-7 ANSWER.<BR>\n" );
document.write( "3X-(-7)=4<BR>\n" );
document.write( "3X+7=4<BR>\n" );
document.write( "3X=4-7<BR>\n" );
document.write( "3X=-3<BR>\n" );
document.write( "X=-3/3<BR>\n" );
document.write( "X=-1 ANSWER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );