document.write( "Question 117615This question is from textbook basic technical mathematics with calculus
\n" ); document.write( ": Solve the linear equations:\r
\n" ); document.write( "\n" ); document.write( "A + B + C = 0
\n" ); document.write( "4A - 10B = 3
\n" ); document.write( "-10B + 5C = 6
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Algebra.Com's Answer #85609 by Fombitz(32388)\"\" \"About 
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1.\"A+%2B+B+%2B+C+=+0\"
\n" ); document.write( "2.\"4A+-+10B+=+3\"
\n" ); document.write( "3.\"-10B+%2B+5C+=+6\"
\n" ); document.write( "The quickest and easiest way is to use equations 2 and 3 and find expressions for A and C in terms of B and then substitute those into equation 1.
\n" ); document.write( "You then solve for B and go back and solve for A and C.
\n" ); document.write( "2.\"4A+-+10B+=+3\"
\n" ); document.write( "\"4A=3%2B10B\"
\n" ); document.write( "\"A=%283%2B10B%29%2F4\"
\n" ); document.write( "3.\"-10B+%2B+5C+=+6\"
\n" ); document.write( "\"5C=6%2B10B\"
\n" ); document.write( "\"C=%286%2B10B%29%2F5\"
\n" ); document.write( "Now go back to equation 1.
\n" ); document.write( "1.\"A+%2B+B+%2B+C+=+0\"
\n" ); document.write( "\"%283%2B10B%29%2F4+%2B+B+%2B%286%2B10B%29%2F5+=+0\"
\n" ); document.write( "Let's multiply both sides by (4*5) to get rid of the denominators.
\n" ); document.write( "\"%283%2B10B%29%2F4+%2B+B+%2B%286%2B10B%29%2F5+=+0\"
\n" ); document.write( "\"5%283%2B10B%29%2B20B%2B4%286%2B10B%29=0\"
\n" ); document.write( "\"15%2B50B%2B20B%2B24%2B40B=0\"
\n" ); document.write( "\"110B%2B39=0\"
\n" ); document.write( "\"110B=-39\"
\n" ); document.write( "\"highlight%28B=-39%2F110%29\"
\n" ); document.write( "From our derivation above for A,
\n" ); document.write( "\"A=%283%2B10B%29%2F4\"
\n" ); document.write( "\"4A=3%2B10%28-39%2F110%29\"
\n" ); document.write( "\"4A=330%2F110-390%2F110%29\"
\n" ); document.write( "\"4A=-60%2F110%29\"
\n" ); document.write( "\"A=-15%2F110%29\"
\n" ); document.write( "\"highlight%28A=-3%2F22%29%29\"
\n" ); document.write( "From equation 1,
\n" ); document.write( "\"A%2BB%2BC=0\"
\n" ); document.write( "\"-15%2F110-39%2F110%2BC=0\"
\n" ); document.write( "\"C=%2839%2B15%29%2F110\"
\n" ); document.write( "\"C=54%2F110\"
\n" ); document.write( "\"highlight%28C=27%2F55%29\"
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