document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117612>Question 117612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much 40% acid solution should be mixed with 2 gallons of 60% acid solution in order to get 50% acid solution? Set up an equation to solve. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85595 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much 40% acid solution should be mixed with 2 gallons of 60% acid solution in order to get 50% acid solution? Set up an equation to solve.<BR>\n" );
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document.write( "Amt of 60% solution = 2 gallons ; amt of active ingredient = 0.6*2 = 1.2 gallons<BR>\n" );
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document.write( "Amt of 40% solution = x gallons; amt of active = 0.4x gallons<BR>\n" );
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document.write( "Amt of mixture = (x+2) gallons; amt of active = 0.5(x+2) gallons<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "1.2 + 0.4x = 0.5(x+2)<BR>\n" );
document.write( "1.2 + 0.4x = 0.5x + 1<BR>\n" );
document.write( "0.1x = 0.2<BR>\n" );
document.write( "x = 2 gallons (amount of 40% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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