document.write( "Question 117601: Thank you for helping. I am trying to help my son with his final review.\r
\n" ); document.write( "\n" ); document.write( "Solve: -3X^2-5x=4\r
\n" ); document.write( "\n" ); document.write( "There are no further directions, such as a method to use
\n" ); document.write( "

Algebra.Com's Answer #85584 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"-3x%5E2-5x=4\" Start with the given equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-3x%5E2-5x-4=0\" Subtract 4 from both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So lets solve \"-3%2Ax%5E2-5%2Ax-4=0\" ( notice \"a=-3\", \"b=-5\", and \"c=-4\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28--5+%2B-+sqrt%28+%28-5%29%5E2-4%2A-3%2A-4+%29%29%2F%282%2A-3%29\" Plug in a=-3, b=-5, and c=-4\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%2A-3%2A-4+%29%29%2F%282%2A-3%29\" Negate -5 to get 5\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-4%2A-3%2A-4+%29%29%2F%282%2A-3%29\" Square -5 to get 25 (note: remember when you square -5, you must square the negative as well. This is because \"%28-5%29%5E2=-5%2A-5=25\".)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25%2B-48+%29%29%2F%282%2A-3%29\" Multiply \"-4%2A-4%2A-3\" to get \"-48\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+-23+%29%29%2F%282%2A-3%29\" Combine like terms in the radicand (everything under the square root)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+i%2Asqrt%2823%29%29%2F%282%2A-3%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+i%2Asqrt%2823%29%29%2F%28-6%29\" Multiply 2 and -3 to get -6\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "After simplifying, the quadratic has roots of\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B+i%2Asqrt%2823%29%29%2F%28-6%29\" or \"x+=+%285+-+i%2Asqrt%2823%29%29%2F%28-6%29\"
\n" ); document.write( "
\n" );