document.write( "Question 117581This question is from textbook Fundamentals of Alg and Trig
\n" ); document.write( ": Hello, I was wondering if there is anyone that could help me with this problem. Any help at all would be greatly appreciated.
\n" ); document.write( "THanks\r
\n" ); document.write( "\n" ); document.write( "A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the body t hours later is given by A(t)=10(0.8)^t and that in order for the drug to be effective, at least 2 milligrams must be in the body.
\n" ); document.write( "a) Determine when 2 milligrams is left in the body?\r
\n" ); document.write( "\n" ); document.write( "b)WHat is the half llife of the drug?
\n" ); document.write( "

Algebra.Com's Answer #85576 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the body t hours later is given by A(t)=10(0.8)^t and that in order for the drug to be effective, at least 2 milligrams must be in the body.
\n" ); document.write( "a) Determine when 2 milligrams is left in the body?
\n" ); document.write( "Let A(t) = 2 and solve for \"t\":
\n" ); document.write( "2 = 10(0.8)^t
\n" ); document.write( "0.2 = (0.8)^t
\n" ); document.write( "Take the log of both sides to get:
\n" ); document.write( "log0.2 = tlog(0.8)
\n" ); document.write( "t = [log0.2/log0.8]
\n" ); document.write( "t = 7.2126 hrs
\n" ); document.write( "-----------------------
\n" ); document.write( "b)WHat is the half life of the drug?
\n" ); document.write( "Let A(t) = (1/2)A(0) and solve for \"t\":
\n" ); document.write( "(1/2)(A(0)) = A(o)(0.8)^t
\n" ); document.write( "0.5 = (0.8)^t
\n" ); document.write( "Take the log:
\n" ); document.write( "t = [log0.5]/[log0.8] = 3.1063 hrs
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );