document.write( "Question 117560: What is the y intercept for this equation:y=x^2+2x-1?\r
\n" ); document.write( "\n" ); document.write( "so far:1=x^2+2x
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Algebra.Com's Answer #85545 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B2x-1=0\" To find the x-intercept, we must set y equal to zero and solve for x\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B2%2Ax-1=0\" ( notice \"a=1\", \"b=2\", and \"c=-1\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+%282%29%5E2-4%2A1%2A-1+%29%29%2F%282%2A1%29\" Plug in a=1, b=2, and c=-1\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4-4%2A1%2A-1+%29%29%2F%282%2A1%29\" Square 2 to get 4 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4%2B4+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-1%2A1\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+8+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+2%2Asqrt%282%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+2%2Asqrt%282%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B+2%2Asqrt%282%29%29%2F2\" or \"x+=+%28-2+-+2%2Asqrt%282%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2F2%2B2%2Asqrt%282%29%2F2\" or \"x=-2%2F2-2%2Asqrt%282%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1%2Bsqrt%282%29\" or \"x=-1-sqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.414213562373095\" or \"x=-2.41421356237309\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0.414213562373095\" or \"x=-2.41421356237309\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B2%2Ax-1\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=0.414213562373095\" and \"x=-2.41421356237309\".So this verifies our answer
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