document.write( "Question 117490: Bob invested $22,000, part at 18% and part at 14%. If the total interest at the end of the year is $3,360, how much did he invest at 18%? \n" ); document.write( "
Algebra.Com's Answer #85540 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Bob invested $22,000, part at 18% and part at 14%. If the total interest at the end of the year is $3,360, how much did he invest at 18%?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt invested at 18%
\n" ); document.write( "Then
\n" ); document.write( "(22000-x) = amt invested at 14%
\n" ); document.write( ":
\n" ); document.write( "A simple interest equation:
\n" ); document.write( ".18x + .14(22000-x) = 3360
\n" ); document.write( ":
\n" ); document.write( ".18x + 3080 - .14x = 3360
\n" ); document.write( ":
\n" ); document.write( ".18x - .14x = 3360 - 3080
\n" ); document.write( ":
\n" ); document.write( ".04x = 280
\n" ); document.write( ":
\n" ); document.write( "x = 280/.04
\n" ); document.write( ":
\n" ); document.write( "x = $7,000 invested at 18%
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check our solution:
\n" ); document.write( "22000 - 7000 = 15000 amt invested at 14%
\n" ); document.write( ":
\n" ); document.write( ".18(7000) + .14(15000) =
\n" ); document.write( " 1260 + 2100 = 3360 \n" ); document.write( "
\n" );