document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117550>Question 117550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you rewrite the equation y=x^2+6x+4 in vertex form by using the concept of completing the sqaure. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85538 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=x^2+6x+4<BR>\n" );
document.write( "=x^2+6x  +4<BR>\n" );
document.write( "=x^2+6x+9+4-9 complete the square by dividing 6 by 2 and squaring the result.<BR>\n" );
document.write( "=(x+3)^2-5<BR>\n" );
document.write( "y=a(x-h)^2+k<BR>\n" );
document.write( "So, a=1 h=-3 and k=-5 and the vertex=(-3,-5)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
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