document.write( "Question 117541:
\n" ); document.write( "Bob invested $22,000, part at 18% and part at 14%. If the total interest at the end of the year is $3,360, how much did he invest at 18%?
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Algebra.Com's Answer #85525 by checkley71(8403)\"\" \"About 
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.18x+.14(22,000-x)=3,360
\n" ); document.write( ".18x+3,080-.14x=3360
\n" ); document.write( ".04x=3360-3080
\n" ); document.write( ".04x=280
\n" ); document.write( "x=280/.04
\n" ); document.write( "x=7,000 answer of amount invested @ 18%.
\n" ); document.write( "22,000-7,000=15,000 invested @ 14%.
\n" ); document.write( "proof
\n" ); document.write( ".18*7,000+.14*15,000=3,360
\n" ); document.write( "1,260+2,100=3,360
\n" ); document.write( "3,360=3,360
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