document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117494>Question 117494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3/5 is added to twice the reciprical of a number, the result is 1. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85523 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be x.<BR>\n" );
document.write( "2/x + 3/5 = 1<BR>\n" );
document.write( "10+3x=5x multiply each side by 5x to eliminate fractions.<BR>\n" );
document.write( "5x-3x=3x-3x+10<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "2*1/5 + 3/5<BR>\n" );
document.write( "=2/5 +3/5 = 1<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );