document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117494>Question 117494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3/5 is added to twice the reciprical of a number, the result is 1. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85522 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/5+2(1/x)=1<BR>\n" );
document.write( "3/5+2/x=1<BR>\n" );
document.write( "2/x=1-3/5<BR>\n" );
document.write( "2/x=2/5 now cross multiply.<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "x=5 answer.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "3/5+2*1/5=1<BR>\n" );
document.write( "3/5+2/5=1<BR>\n" );
document.write( "1=1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );