document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117496>Question 117496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "the sum of the recipricals of two consecutive integers is 7/12. find the two intergers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85520 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the integers be x & (x+1).<BR>\n" );
document.write( "(1/x)+[1/(x+1)]=7/12 find a common denominator and combine these fractions on the left. x(x+1) <BR>\n" );
document.write( "(x+1+x)/x(x+1)=7/12<BR>\n" );
document.write( "(2x+1)/(x^2+x)=7/12 now cross multiply<BR>\n" );
document.write( "7(x^2+x)=12(2x+1)<BR>\n" );
document.write( "7x^2+7x=24x+12<BR>\n" );
document.write( "7x^2+7x-24x-12=0<BR>\n" );
document.write( "7x^2-17x-12=0<BR>\n" );
document.write( "(7x+4)(x-3)=0<BR>\n" );
document.write( "x-3=0<BR>\n" );
document.write( "x=3 answer<BR>\n" );
document.write( "so the integers are 3 & 4<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "1/3+1/4=7/12<BR>\n" );
document.write( "(4+3)/12=7/12<BR>\n" );
document.write( "7/12=7/12 </SPAN>\n" );
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