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document.write( "the sum of the recipricals of two consecutive integers is 7/12. find the two intergers \n" );
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Algebra.Com's Answer #85514 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let the integers be x and x+1 \n" ); document.write( "1/x + 1/(x+1) = 7/12 \n" ); document.write( "12(x+1)+12x=7x(x+1) Multiply each side by 12x(x+1) to eliminate fractions. \n" ); document.write( "12x+12+12x=7x^2+7x \n" ); document.write( "7x^2-17x-12=0 \n" ); document.write( "7*-12=-84 What factors of -84 when added equal -17? Ans.: -21, 4 \n" ); document.write( "7x^2-21x+4x-12 \n" ); document.write( "7x(x-3)+4(x-3) Factor by grouping. \n" ); document.write( "(7x+4)(x-3)=0 \n" ); document.write( "x=3 only answer that is an integer. \n" ); document.write( "3, 4 Ans. \n" ); document.write( ". \n" ); document.write( "Check: \n" ); document.write( "1/3 + 1/4 \n" ); document.write( "=4/12 + 3/12 \n" ); document.write( "=7/12 \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |