document.write( "Question 117496: \r
\n" ); document.write( "\n" ); document.write( "the sum of the recipricals of two consecutive integers is 7/12. find the two intergers
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Algebra.Com's Answer #85514 by edjones(8007)\"\" \"About 
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Let the integers be x and x+1
\n" ); document.write( "1/x + 1/(x+1) = 7/12
\n" ); document.write( "12(x+1)+12x=7x(x+1) Multiply each side by 12x(x+1) to eliminate fractions.
\n" ); document.write( "12x+12+12x=7x^2+7x
\n" ); document.write( "7x^2-17x-12=0
\n" ); document.write( "7*-12=-84 What factors of -84 when added equal -17? Ans.: -21, 4
\n" ); document.write( "7x^2-21x+4x-12
\n" ); document.write( "7x(x-3)+4(x-3) Factor by grouping.
\n" ); document.write( "(7x+4)(x-3)=0
\n" ); document.write( "x=3 only answer that is an integer.
\n" ); document.write( "3, 4 Ans.
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\n" ); document.write( "Check:
\n" ); document.write( "1/3 + 1/4
\n" ); document.write( "=4/12 + 3/12
\n" ); document.write( "=7/12
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