document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117530>Question 117530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the equation if the line perpendicular to y= 2x + 7 and is passing through (1, -8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85513 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the equation if the line perpendicular to y= 2x + 7 and is passing through (1, -8)<BR>\n" );
document.write( "The given equation has a slope of 2; so the perpendicular line must have<BR>\n" );
document.write( "a slope of -1/2. In addition, it passes thru (1,-8)<BR>\n" );
document.write( "Substitute those values into y = mx+b to solve for \"b\":<BR>\n" );
document.write( "-8 = (-1/2)*1 + b <BR>\n" );
document.write( "b = -8+(1/2) = -15/2<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "y = (-1/2)x-(15/2) is the equation you want.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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