document.write( "Question 117531: solve: the absoulute value of 2x-1 over 3 is greater than or equal to 4.\r
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Algebra.Com's Answer #85511 by stanbon(75887)\"\" \"About 
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solve: the absoulute value of 2x-1 over 3 is greater than or equal to 4.
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\n" ); document.write( "|(2x-1)/3| >=4
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\n" ); document.write( "This means:
\n" ); document.write( "(2x-1)/3 >=4 or (2x-1)/3 <- -4
\n" ); document.write( "2x-1>=12 or 2x-1<=-12
\n" ); document.write( "2x>=13 or 2x<=-11
\n" ); document.write( "x >= 13/2 or x <= -11/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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