document.write( "Question 17689: Express the Area A of an isoceles triangle with a height of 8 inches and a base of b inches as a function of the length s of one of its two equal sides.\r
\n" ); document.write( "\n" ); document.write( "I got this far\r
\n" ); document.write( "\n" ); document.write( "A=1/2bh. b=A/4
\n" ); document.write( "P=s+s+b, 2s+A/4\r
\n" ); document.write( "\n" ); document.write( "now how do I find the A as a function of s?\r
\n" ); document.write( "\n" ); document.write( "thanks \n" ); document.write( "
Algebra.Com's Answer #8551 by venugopalramana(3286)\"\" \"About 
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Express the Area A of an isoceles triangle with a height of 8 inches and a base of b inches as a function of the length s of one of its two equal sides
\n" ); document.write( "let the isocelles triangle be PQR with QR as base =b and equal sides PQ=PR=s,Let PS=h be the altitude from P to QR.since PQR is isocelles triangle QS=SR=b/2.further PQS is a right angled triangle.hence
\n" ); document.write( "PQ^2=QS^2+PS^2
\n" ); document.write( "s^2=(b/2)^2+h^2 or.s^2-h^2=b^2/4..or..b=Square root of [4(s^2-64)]
\n" ); document.write( "area =A = (1/2)*b*h=8*b/2=4b = 4*Square root of [4(s^2-64)]...........
\n" ); document.write( "A=8*Square root of [(s^2-64)]=
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