document.write( "Question 117536: A passenger train can travel 325 miles in the same time a freight train takes to travel 200 miles. If the speed of the passenger train is 25 miles per hour faster than the speed of the freight train, find the speed of each. \n" ); document.write( "
Algebra.Com's Answer #85509 by stanbon(75887)\"\" \"About 
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A passenger train can travel 325 miles in the same time a freight train takes to travel 200 miles. If the speed of the passenger train is 25 miles per hour faster than the speed of the freight train, find the speed of each.
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\n" ); document.write( "Passenger Train DATA:
\n" ); document.write( "Distance = 325 miles ; Rate = x + 25 mph ; Time = d/r = 325/(x+25) hrs.
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\n" ); document.write( "Freight Train DATA:
\n" ); document.write( "Distance = 200 miles ; Rate = x mph ; Time = d/r = 200/x hrs.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time = time
\n" ); document.write( "325/(x+25) = 200/x
\n" ); document.write( "325x = 200(x+25)
\n" ); document.write( "125x = 200*25
\n" ); document.write( "x = 200/5
\n" ); document.write( "x = 40 mph (Freight train Rate)
\n" ); document.write( "x+25 = 65 mph ( Passenger train Rate)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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