document.write( "Question 117515: Please help me with this problem. I have similar problems in my homework but it does not show how to solve this type of problem. You help is appreciated.
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document.write( "Problem: 6y over y^2+5y+4 add to 4y over y^2-1. I tried to factor the first denominator but that just got me more confused. I don't know where to start. \n" );
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Algebra.Com's Answer #85492 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 6y/(y^2+5y+4)+4y/(y^2-1) \n" ); document.write( "=6y/((y+4)(y+1))+4y/((y+1)(y-1)) Factor the denominators. \n" ); document.write( "=(6y(y-1)+4y(y+4))/((y+4)(y+1)(y-1)) LCD is the denominator \n" ); document.write( "=6y^2-6y+4y^2+16y/((y+4)(y+1)(y-1)) Expand the numerator. \n" ); document.write( "=10y^2+10y/((y+4)(y+1)(y-1)) Combine terms. \n" ); document.write( "= \n" ); document.write( "=10y/((y+4)(y-1)) Voila! \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |