document.write( "Question 117515: Please help me with this problem. I have similar problems in my homework but it does not show how to solve this type of problem. You help is appreciated.
\n" ); document.write( "Problem: 6y over y^2+5y+4 add to 4y over y^2-1. I tried to factor the first denominator but that just got me more confused. I don't know where to start.
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Algebra.Com's Answer #85492 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
6y/(y^2+5y+4)+4y/(y^2-1)
\n" ); document.write( "=6y/((y+4)(y+1))+4y/((y+1)(y-1)) Factor the denominators.
\n" ); document.write( "=(6y(y-1)+4y(y+4))/((y+4)(y+1)(y-1)) LCD is the denominator
\n" ); document.write( "=6y^2-6y+4y^2+16y/((y+4)(y+1)(y-1)) Expand the numerator.
\n" ); document.write( "=10y^2+10y/((y+4)(y+1)(y-1)) Combine terms.
\n" ); document.write( "=\"10y%2Across%28y%2B1%29%2F%28%28y%2B4%29cross%28y%2B1%29%28y-1%29%29\"
\n" ); document.write( "=10y/((y+4)(y-1)) Voila!
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