document.write( "Question 117495: the numerator of a certain fraction is 2 more than the denomenator. if 1/3 is added to the fracgion, the result is 2. find the fraction \n" ); document.write( "

Algebra.Com's Answer #85482 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Let x = the denominator
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\n" ); document.write( "\"the numerator of a certain fraction is 2 more than the denomenator.
\n" ); document.write( " $\"%28%28x%2B2%29%29%2Fx\"$
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\n" ); document.write( "\"if 1/3 is added to the fraction, the result is 2\"
\n" ); document.write( " $\"%28%28x%2B2%29%29%2Fx\"$ + $\"1%2F3\"$ = 2
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\n" ); document.write( "find the fraction
\n" ); document.write( "Multiply equation by 3x to eliminate the denominators
\n" ); document.write( "3x* $\"%28%28x%2B2%29%29%2Fx\"$ + 3x* $\"1%2F3\"$ = 3x(2)
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\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "3(x+2) + 1x = 6x
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\n" ); document.write( "3x + 6 + x = 6x
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\n" ); document.write( "4x + 6 = 6x
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\n" ); document.write( "6 = 6x - 4x
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\n" ); document.write( "6 = 2x
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\n" ); document.write( "x = $\"6%2F2\"$
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\n" ); document.write( "x = 3
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\n" ); document.write( "Check our solution in original equation
\n" ); document.write( " $\"%28%283%2B2%29%29%2F3\"$ + $\"1%2F3\"$ = 2
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\n" ); document.write( " $\"%285%29%2F3\"$ + $\"1%2F3\"$ = 2; confirms our solution
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\n" ); document.write( "Did I make this understandable, any questions?
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