document.write( "Question 998682: solve for x\r
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document.write( "x= 6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)\r
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document.write( "I am not sure how to find X, I would appreciate if someone can help me. I will provide my step.\r
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document.write( "x=6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64)\r
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document.write( " =6/8 (log(base6) sqrt(108)/ (2/sqrt3) + log(base 6) 9^2 + log(base6) 64)\r
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document.write( " =6/8 (log(base6) sqrt(108) / (2/sqrt3) + log(base 6) (81)(64)\r
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document.write( " =6/8 (log(base6) 9 + log(base6) 5184)
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document.write( " =6/8 (log(base6) (9)(5184)\r
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document.write( " =6/8 (log(base6) 46656)\r
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document.write( " = log(base6) 34992\r
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Algebra.Com's Answer #854702 by greenestamps(13367) You can put this solution on YOUR website! \n" ); document.write( "solve for x \n" ); document.write( "x= 6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64) \n" ); document.write( "I am not sure how to find X, I would appreciate if someone can help me. I will provide my step. \n" ); document.write( "x=6/8 (log(base6) sqrt(108) - 1 log(base6) (2/sqrt(3))+ 2 log (base6) 9 + log(base6) 64) \n" ); document.write( "=6/8 (log(base6) sqrt(108)/ (2/sqrt3) + log(base 6) 9^2 + log(base6) 64) \n" ); document.write( "=6/8 (log(base6) sqrt(108) / (2/sqrt3) + log(base 6) (81)(64) \n" ); document.write( "=6/8 (log(base6) 9 + log(base6) 5184)\r \n" ); document.write( "\n" ); document.write( "=6/8 (log(base6) (9)(5184) \n" ); document.write( "=6/8 (log(base6) 46656) \n" ); document.write( "= log(base6) 34992 \n" ); document.write( "------------------------------------------------------------------ \n" ); document.write( "Your work is fine up to the last step. \n" ); document.write( "It will be easier to find the answer if you leave the expression in factored form instead of multiplying all the numbers together. \n" ); document.write( "The entire expression is of the form \n" ); document.write( "(6/8) (... extended expression in a form equivalent to \"log (base6) of A\") \n" ); document.write( "Let's drop all the \"log (base 6)\" notations and just look at the \"A\". Using basic log rules, A is as follows: \n" ); document.write( " \n" ); document.write( "Performing basic arithmetic WITHOUT multiplying all the numbers together.... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "And now remembering that we are looking for the value of the log base 6 of this number.... \n" ); document.write( " \n" ); document.write( "Finally, then.... \n" ); document.write( " \n" ); document.write( "ANSWER: 9/2 \n" ); document.write( " \n" ); document.write( " |