document.write( "Question 686655: log(x-44)-log7=log(x-14)-logx solve.\r
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Algebra.Com's Answer #854671 by MathTherapy(10858)\"\" \"About 
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document.write( "log(x-44)-log7=log(x-14)-logx solve.\r\n" );
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document.write( "also this question logx+log(x-3)=1\r\n" );
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document.write( "This respondent, @MathLover1(20855) did the same thing that @HyperBrain(694) did  for Problem, logarithm/105757. She used the QUADRATIC\r\n" );
document.write( "EQUATION formula to solve both quadratic equations, which is UNNECESSARY, since the resultant TRINOMIAL is FACTORABLE! Furthermore, the\r\n" );
document.write( "problem, log(x - 44) - log 7 = log (x - 14) - log (x), has x - 44 as its SMALLEST log variable-argument. This MUST BE > 0, which means that x > 44. \r\n" );
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document.write( "So, the equation, log(x - 44) - log 7 = log (x - 14) - log (x), will have the following criteria, x > 44.\r\n" );
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document.write( "She got 2 values for x: x = 49, and x = 2. Obviously, 2 is NOT > 44, so x = 2 is an EXTRANEOUS solution, which makes x = 49, VALID/ACCEPTABLE,\r\n" );
document.write( "and the SOLE SOLUTION.
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