document.write( "Question 105757: Solve logx + log(x-48) = 2 \n" ); document.write( "

Algebra.Com's Answer #854669 by MathTherapy(10858) $\"\"$ $\"About$

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document.write( "Solve logx + log(x-48) = 2\r\n" );
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document.write( "As usual, HyperBrain(694)'s solution is PARTIALLY-CORRECT/WRONG.\r\n" );
document.write( "Furthermore, the TRINOMIAL,  can be factorized into (x - 50)(x + 2), so, using the QUADRATIC EQUATION formula is UNNECESSARY,\r\n" );
document.write( "as it NOTICEABLY generates LARGE numbers, which most of us deplore!! Unless, of course, one wishes to do so! \r\n" );
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document.write( "log (x) + log (x - 48) = 2\r\n" );
document.write( "Finally, as the SMALLER of the 2 log variable-arguments, x - 48 MUST be > 0, we get: x - 48 > 0_____x > 48.\r\n" );
document.write( "So, equation becomes: log (x) + log (x - 48) = 2, with x > 48.\r\n" );
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document.write( "One of the respondent's 2 solutions, - 2 is NOT > 48, which makes it, EXTRANEOUS. Obviously, the other solution, x = 50 is EFINITELY > 48, making\r\n" );
document.write( "it VALID/ACCEPTABLE, and therefore, the SOLE SOLUTION.

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