document.write( "Question 207535: Solve for x where x is a real number\r
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document.write( "log x + log (x-3) = 1 \n" );
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Algebra.Com's Answer #854664 by ikleyn(53937) You can put this solution on YOUR website! . \n" ); document.write( "Solve for x where x is a real number \n" ); document.write( "log x + log (x-3) = 1 \n" ); document.write( "~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In his post, @HyperBrain derives two solutions x = 5 and/or x = -2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But the negative solution can not be accepted: it must be rejected, \n" ); document.write( "since logarithm does not tolerate negative arguments !\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |