document.write( "Question 945236: find the measures of the angles of a triangle if the measure of one side is twice the measure of a second and the third angle measures two times the second decreased by 20 \n" ); document.write( "

Algebra.Com's Answer #854635 by greenestamps(13367) $\"\"$ $\"About$

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\n" ); document.write( "find the measures of the angles of a triangle if the measure of one $\"cross%28side%29\"$ angle is twice the measure of a second and the third angle measures two times the second decreased by 20

\n" ); document.write( "One angle (the \"first\" angle) has a measure equal to twice the measure of the second angle; the third angle has a measure that is 20 less than twice the measure of the second angle. So

\n" ); document.write( "x = second angle measure
\n" ); document.write( "2x = first angle measure
\n" ); document.write( "2x-20 = third angle measure

\n" ); document.write( "The sum of the angles of a triangle is 180 degrees:

\n" ); document.write( "(x)+(2x)+(2x-20) = 180
\n" ); document.write( "5x-20 = 180
\n" ); document.write( "5x = 200
\n" ); document.write( "x = 40

\n" ); document.write( "ANSWERS: the angle measures in degrees are x=40, 2x=80, and 2x-20 = 60

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