document.write( "Question 945054: the sum of three consecutive numbers is 56. the second is five less than the first and the third is 15 more than the smallest. find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #854633 by greenestamps(13362)\"\" \"About 
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\n" ); document.write( "The description of the relationships between the three numbers clearly indicates that the three numbers are NOT consecutive numbers. So we need to ignore the statement that says the numbers are consecutive.

\n" ); document.write( "In the solution by @josgarithmetic, the given information is not reflected correctly in the setup, so the solution is not right.

\n" ); document.write( "The second number is 5 less than the first, and the third number is 15 more than the smallest. So the smallest number is the second number:

\n" ); document.write( "x = second (smallest) number
\n" ); document.write( "x+5 = first number
\n" ); document.write( "x+15 = third number

\n" ); document.write( "The sum of the three numbers is 56:

\n" ); document.write( "(x)+(x+5)+(x+15) = 56
\n" ); document.write( "3x+20 = 56
\n" ); document.write( "3x = 36
\n" ); document.write( "x = 12

\n" ); document.write( "The three (not consecutive) numbers are x=12; x+5=17, and x+15=27.

\n" ); document.write( "ANSWERS: 12, 17, and 27

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