document.write( "Question 742189: Solve and check
\n" ); document.write( "a) 2log(x-1) = 2+ log 100 \n" ); document.write( "
Algebra.Com's Answer #854630 by MathTherapy(10858)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Solve and check\r\n" );
document.write( "a) 2log(x-1) = 2+ log 100\r\n" );
document.write( "*************************\r\n" );
document.write( "The response from @josgarithmetic(39831), while correct, is confusing, in this author's opinion. Whenever one sees a log argument without a base,\r\n" );
document.write( "it's widely known that that base is 10, since that's the base/number system we all work in. This is just the same as x. It's known that this is actually\r\n" );
document.write( "1x, but it's not written like that, just x. Also, x is actually \"x%5E1\", but again, it's not written as such, just x. So, why confuse a person by working the\r\n" );
document.write( "problem without a base, just because a base wasn't stated? That base, as stated before, is OBVIOUSLY no other than 10. \r\n" );
document.write( "\r\n" );
document.write( "          2 log(x - 1) = 2 + log (100)\r\n" );
document.write( "          2 log(x - 1) = 2 + 2 ---- log (100) = 2\r\n" );
document.write( "          2 log(x - 1) = 4\r\n" );
document.write( "\"%282%28log%28%28x+-+1%29%29%29%29%2F2+=+4%2F2\" ----- Dividing each side by 2 \r\n" );
document.write( "            log (x - 1) = 2\r\n" );
document.write( "                     \"x+-+1+=+10%5E2\" ---- Converting to EXPONENTIAL form\r\n" );
document.write( "                     x - 1 = 100\r\n" );
document.write( "                           x = 100 + 1 = 101\r\n" );
document.write( "\r\n" );
document.write( "You can do the CHECK!!
\n" ); document.write( "
\n" );