document.write( "Question 946643: Solve fora in log(2a)- 3log2= 1/2log(a-3) \n" ); document.write( "
Algebra.Com's Answer #854615 by ikleyn(53937) You can put this solution on YOUR website! . \n" ); document.write( "Solve for a in log(2a)- 3log2= 1/2log(a-3). \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " @lwsshar3 in his post gives the answer \"no real solutions\".\r \n" ); document.write( "\n" ); document.write( " This answer is incorrect.\r \n" ); document.write( "\n" ); document.write( " I came to bring a correct solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(2a)- 3log2 = 1/2*log(a-3) \n" ); document.write( "log(2a/(2^3)) = log((a-3)^(1/2)) \n" ); document.write( "2a/8 = (a-3)^(1/2) \n" ); document.write( "a/4 = sqrt(a-3) \n" ); document.write( "a = 4*sqrt(a-3) \n" ); document.write( "square both sides: \n" ); document.write( "a^2 = 16*(a-3) \n" ); document.write( "a^2 = 16a - 48 \n" ); document.write( "a^2 - 16a + 48 = 0 \n" ); document.write( "Discriminant d = b^2-4ac = (-16)^2 - 4*16*48 = 64\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The solutions are a = 12 and a = 4. ANSWER\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Both solutions satisfy the original equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |