document.write( "Question 957182: A cruise ship can sail 25 mph in calm water. Sailing with the Gulf Stream, the ship can sail 256 mi in the same amount of time it takes to sail 144 mi against the Gulf Stream. Find the rate of the Gulf Stream. \n" ); document.write( "

Algebra.Com's Answer #854604 by MathTherapy(10855) $\"\"$ $\"About$

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document.write( "A cruise ship can sail 25 mph in calm water. Sailing with the Gulf Stream, the ship can sail 256 mi in the same amount of time it takes to sail 144 mi against the Gulf Stream. Find the rate of the Gulf Stream. \r\n" );
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document.write( "Let the stream's rate, be C\r\n" );
document.write( "Then, the DOWNSTREAM rate (rate with the stream) is 25 + C, or 25 + C\r\n" );
document.write( "Also, the UPSTREAM rate (rate against the stream) is: S - C, or 25 - C \r\n" );
document.write( "With the DOWNSTREAM-DISTANCE being 256 mi, time the ship takes to travel said distance is: \r\n" );
document.write( "And, with the UPSTREAM-DISTANCE being 144 mi, time the ship takes to travel said distance is: \r\n" );
document.write( "As the times are the same, we get: \r\n" );
document.write( "                                                    144(25 + C) = 256(25 - C) ------ Cross-multiplying\r\n" );
document.write( "                                                        9(25 + C) = 16(25 - C) ------ Dividing both sides by 8\r\n" );
document.write( "                                                      9(25) + 9C = 16(25) - 16C\r\n" );
document.write( "                                                         9C + 16C = 16(25) - 9(25)\r\n" );
document.write( "                                                                  25C = 7(25)\r\n" );
document.write( "                                        Stream's rate, or

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