Algebra.Com's Answer #854597 by n2(91)  You can put this solution on YOUR website! . \n" );
document.write( "Michael drove to work on Monday at 45 mph and arrived one minute early. \n" );
document.write( "The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arriving one minute late. \n" );
document.write( "How far does Michael live from work? What speed does he need to drive to arrive 5 minutes early? \n" );
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document.write( "Let 'd' be the distance from home to work (the same as the returning distance), in miles.\r\n" );
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document.write( "The time Michael spent on Monday was hours (the distance divided by the average speed).\r\n" );
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document.write( "The time Michael spent on Tuesday was hours (the distance divided by the average speed).\r\n" );
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document.write( "These two time intervals differ in 1 + 1 = 2 minutes.\r\n" );
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document.write( "So, we write this \"time equation\" \r\n" );
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document.write( "To solve, multiply both sides by 40*45. You will get\r\n" );
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document.write( " 45d - 40d = \r\n" );
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document.write( " 5d = 60\r\n" );
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document.write( " d = 60/5 = 12.\r\n" );
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document.write( "So. the distance from home to work is 12 miles.\r\n" );
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document.write( "Thus first question is answered.\r\n" );
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document.write( "To answer second question, calculate the travel time on Monday. \r\n" );
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document.write( "It is of a hour, which is the same as of an hour, or 16 minutes.\r\n" );
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document.write( " | So, if Michaels leaves his home at the same time |\r\n" );
document.write( " | every day (as the problem states), |\r\n" );
document.write( " | he has 16+1 = 17 minutes to get the office on time. |\r\n" );
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document.write( "To get the office 5 minutes earlier the control time, the travel time should be 17-5 = 12 minutes, or of an hour.\r\n" );
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document.write( "Hence, to get the office 5 minutes earlier the control time, his average speed should be = 60 miles per hour.\r\n" );
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document.write( "It is the answer to the second question.\r\n" );
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document.write( "At this point, the problem is solved completely.\r \n" );
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