document.write( "Question 1163329: If you are in shallow water and look at an object below the surface of the water,
\n" ); document.write( "the object will look farther away from you than it really is. This is because as light passes
\n" ); document.write( "through air and water it bends or refracts the light rays. The index of refraction for water is 1.33.
\n" ); document.write( "This is the ratio of the sine of theta 1 and the sine of theta 2.\r
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\n" ); document.write( "\n" ); document.write( "a)You are in 2 feet of water in the shallow end of a pool. You look down at some goggles at angle
\n" ); document.write( "(theta=60) degrees measured from a line perpendicular to the surface of the water. Find (theta 2 ) \r
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\n" ); document.write( "\n" ); document.write( "b) Find the distances x and y
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Algebra.Com's Answer #854592 by KMST(5396)\"\" \"About 
You can put this solution on YOUR website!
I agree with ikleyn and CPhill, but I would like to draw and overexplain as usual.
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\n" ); document.write( "\"drawing%2820%2C30%2C0%2C0.4%2C-0.6%2C0%2C%0D%0Alocate%280.39%2C0%2Ctheta%29%0D%0A%29\"\"1\"\"%22=%22\"\"60%5Eo\" (given)
\n" ); document.write( "\"drawing%2820%2C30%2C0%2C0.4%2C-0.6%2C0%2C%0D%0Alocate%280.39%2C0%2Ctheta%29%0D%0A%29\"\"2\" value calculated based on Snell's Law: \"%22sin%28%22\"\"theta\"\"%221%29%22\"\"%22=%22\"\"n%2A%22sin%28%22\"\"theta\"\"%222%29%22\"
\n" ); document.write( "\"sin%2860%5Eo%29\"\"%22=%22\"\"1.33%2A%22sin%28%22\"\"theta\"\"%222%29%22\"-->\"sqrt%283%29%2F2\"\"%22=%22\"\"1.33%2A%22sin%28%22\"\"theta\"\"%222%29%22\"-->\"sqrt%283%29%2F2%2F1.33\"\"%22=%22\"\"%22sin%28%22\"\"theta\"\"%222%29%22\"
\n" ); document.write( "From that we can find \"theta\"\"%222%29%22\"\"%22=%22\"\"highlight%2840.63%5Eo%29\" (rounded)
\n" ); document.write( "We can also find \"%22cos%28%22\"\"theta\"\"%222%29%22\" ,
\n" ); document.write( "\"%22tan%28%22\"\"theta\"\"%222%29%22\", and the distance
\n" ); document.write( "\"2ft%2A%22tan%28%22\"\"theta\"\"%222%29%22=highlight%281.716ft%29\" (rounded)
\n" ); document.write( "Independently of refraction, we can find the distance
\n" ); document.write( "\"2ft%2A%22tan%28%22\"\"theta\"\"%221%29%22\"\"%22=%22\"\"2ft%2Atan%2860%5Eo%29=2ft%2Asqrt%283%29=highlight%283.464ft%29\" (rounded)
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