document.write( "Question 117457: A bag contains 10 blue, 6 red, and 4 green rubber balls. If you select a ball at random from the bag, what is the probability of not choosing a green ball?\r
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document.write( "A. 1/5
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document.write( "B. 4/5
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document.write( "C. 5/6
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document.write( "D. 9/10\r
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document.write( "Why can you eliminate choice D in this question? \n" );
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Algebra.Com's Answer #85459 by Fombitz(32388) You can put this solution on YOUR website! The total number of balls available is 10+6+4=20 balls. \n" ); document.write( "The probability of choosing a blue ball is 10/20. \n" ); document.write( "The probability of choosing a red ball is 6/20. \n" ); document.write( "The probability of choosing a green ball is 4/20. \n" ); document.write( "P(green or not green) = 1, since the ball I choose must be either green or not green. \n" ); document.write( "P(green) + P(not green) = P(green or not green) \n" ); document.write( "4/20 + P(not green) = 1 \n" ); document.write( "P(not green) = 16/20 = 4/5 \n" ); document.write( "The answer is B. \n" ); document.write( "You can eliminate D because none of the probability can sum to 18 out of 20(9/10). The only possible choices are 16/20, 14/20, or 10/20. \n" ); document.write( "You can also eliminate C because it's not possible to sum to repeating fraction from the possible probabilities (0.5,0.3,0.2). \n" ); document.write( " |