document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971955>Question 971955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A metal worker has a metal alloy that is 30% copper and another alloy that is 80% copper. How many kilograms of each alloy should the metalworker combine to creat 60 kilograms of a 51% copper alloy?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #854521 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13355)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=854521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Two other tutors have provided essentially identical solutions using the standard formal algebraic method for solving 2-part mixture problems like this.<br><BR>\n" );
document.write( "Here is a solution using a less formal method that can be used to solve any problem like this.  The method can be especially fast and easy, especially if the numbers in the problem are \"nice\".<br><BR>\n" );
document.write( "(1) Use a number line if it helps to observe/calculate that 51% is 21/50 of the way from 30% to 80%.<BR>\n" );
document.write( "(2) That means 21/50 of the mixture should be the alloy that is 80% copper.<br><BR>\n" );
document.write( "21/50 of 60 kg is (.42)(60) = 25.2 kg.<br><BR>\n" );
document.write( "ANSWER: 25.2 kg of the 80% copper alloy and (60-25.2)=34.8 kg of the 30% copper alloy.<br><BR>\n" );
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