document.write( "Question 975870: A and B are playing tag . A stay still while B runs from the same spot at a rate 2 meters per second.
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document.write( "After 60 seconds B keeps running . A now runs after him at a rate of 3 meters per second.
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document.write( "How long has A run when he caught up to B\r
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document.write( "My solution
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document.write( "3 (t-60) = 2t
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document.write( "3t - 180 =2t
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document.write( "3t-2t =180
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document.write( "t = 180 \n" );
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Algebra.Com's Answer #854487 by ikleyn(53937) You can put this solution on YOUR website! . \n" ); document.write( "A and B are playing tag . A stay still while B runs from the same spot at a rate 2 meters per second. \n" ); document.write( "After 60 seconds B keeps running . A now runs after him at a rate of 3 meters per second. \n" ); document.write( "How long has A run when he caught up to B\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "My solution \n" ); document.write( "3 (t-60) = 2t \n" ); document.write( "3t - 180 =2t \n" ); document.write( "3t-2t =180 \n" ); document.write( "t = 180 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your error is that you determined the time for B, \n" ); document.write( "while the problem asks about the time for A.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |