document.write( "Question 918440: A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 36.900 ft. give the area A of the window in square feet when the width is 7.500 ft. Give the answer to two decimal places.
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Algebra.Com's Answer #854471 by MathTherapy(10839) $\"\"$ $\"About$

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document.write( "A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 36.900 ft. give\r\n" );
document.write( "the area A of the window in square feet when the width is 7.500 ft. Give the answer to two decimal places.\r\n" );
document.write( "I'm stuck and I need this one to finish my homework! Even my dad can't help me and I got no results from google and my math\r\n" );
document.write( "book only uses rectangular examples!!! PLEASE HELP ME!!!!\r\n" );
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document.write( "Respondent @josgaritmetic presumes that additional info is needed to determine the area in this problem. Quite the contrary!   \r\n" );
document.write( "  .\r\n" );
document.write( "This problem was redone and corrected, since the width and perimeter were erroneously entered before as 7,500 and 36,900,\r\n" );
document.write( "respectively, instead of 7.5' and 36.9', respectively \r\n" );
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document.write( "      Width (W), or DC = 7.5’\r\n" );
document.write( "Diameter of semi-circle = AB = DC = W = 7.5'\r\n" );
document.write( "   Perimeter (GIVEN) = 36.9’\r\n" );
document.write( "Perimeter of window = BCDA + length of arc of semi-circle AB \r\n" );
document.write( "                                     = L + W + L + circumference of semicircle (length of arc AB) \r\n" );
document.write( "                                     = W + 2L + circumference of semicircle (length of arc AB)\r\n" );
document.write( "                             36.9 = 7.5 + 2L + ꙥD ---- Substituting 36.9 for perimeter, 7.5 for W, and ꙥD for circumference of\r\n" );
document.write( "                                                                                  semi-circle, AB\r\n" );
document.write( "                             36.9 = 7.5 + 2L + ꙥAB\r\n" );
document.write( "                             36.9 = 7.5 + 2L + 7.5ꙥ\r\n" );
document.write( "                             36.9 = 7.5 + 2L + 3.75ꙥ\r\n" );
document.write( "       36.9 - 7.5 - 3.75ꙥ = 2L\r\n" );
document.write( "                29.4 - 3.75ꙥ = 2L\r\n" );
document.write( "           \r\n" );
document.write( "                             8.81' = L              \r\n" );
document.write( "Area of rectangle, ABCD: LW = 8.81(7.5) = 66.075 sq ft\r\n" );
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document.write( "Diameter of semi-circle, AB = AB\r\n" );
document.write( "Radius (r) = D = AB = 7.5 = 3.75’\r\n" );
document.write( "Area of semi-circle AB =  \r\n" );
document.write( "                                      = ꙥ ---- Substituting 3.75 for r \r\n" );
document.write( "                                      = (14.0625ꙥ) \r\n" );
document.write( "                                      = (44.17864) = 22.08932 sq ft\r\n" );
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document.write( "Area of the window = Area of rectangle, ABCD + Area of semi-circle AB \r\n" );
document.write( "                                          =             66.075 sq ft         +        22.08932 sq ft = 88.16432, or approximately 88.16 sq ft

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